Question

2. Write four solutions for each of the following equations:
(ii) πx + y = 9​

Answer 1

Answer:

AnswEr:

We have,

πx + y = 9

\sf\green{Substituting\:x=0\:in\:this\:equation,\:we\:get}Substitutingx=0inthisequation,weget

\bf \: x \times 0 + y = 9 = > 0 + y = 9 = > y = 9x×0+y=9=>0+y=9=>y=9

So, ( 0 , 9 ) is a solution of the given equation.

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\sf\blue{Substituting\:x=1\:in\:this\:equation,\:we\:get}Substitutingx=1inthisequation,weget

\begin{gathered} \bf \: x \times 1 + y = 9 \\ = \bf \: \pi + y = 9 \\ \bf y = 9 - \pi\end{gathered}

x×1+y=9

=π+y=9

y=9−π

So, ( 1, 9 - π ) is solution of the given equation.

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Similarly, by substituting x = -1 and x = 2 respectively, we obtain ( -1 , 9 + π ) and ( 2,9 - 2π ) as solutions of the given equation.