Question

2) Write the correct decreasing order of boiling point for bromomethane, chloroform , dibromomethane and
bromoform
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Answer 1

Answer:

Answer:The decreasing order of boiling point is, bromoform (CHBr3) > dibromomethane (CH2Br2) > chloroform (CHCl3) > bromomethane (CH3Br).

Answer:The decreasing order of boiling point is, bromoform (CHBr3) > dibromomethane (CH2Br2) > chloroform (CHCl3) > bromomethane (CH3Br).Explanation:

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Answer 2

The correct decreasing order of boiling point for the given compounds is dibromomethane > bromoform > chloroform > bromomethane.

• Dibromomethane (CH2Br2) has the greatest boiling point due to its huge molecular weight, dipole-dipole interactions, and van der Waals forces between its molecules.
• Bromoform (CHBr3) has the second-highest boiling point among all organic compounds because of how its molecules interact with one another through dipole-dipole interactions and van der Waals forces.
• Chloroform (CHCl3) has a lower boiling point than dibromomethane and bromoform due to its lower molecular weight and weaker dipole-dipole interactions.
• The lowest boiling point of all the compounds is that of bromomethane (CH3Br), which has the smallest molecular weight, the fewest dipole-dipole interactions, and the fewest van der Waals forces between its molecules.

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