Question

(2) Write the first four terms of the following Arithmetic Progressions where the common difference 'd' and the first term 'a' are given. (i) a = 3, d = 2 (iii) a = 5, d = 7 (v) a = 8, d = 0 (ii) a = 8, d=-2.5 (iv) a = -3, d = -4 (vi) a = 6, d=-6​

Answer 1

Answer:

Step-by-step explanation:

Area of the Rhombus is 25 cm² (approx).

According to the Question

It is given that ,

Side of rhombus = 5cm

Length of one diagonal ,d1 = 8cm

we have to calculate the area of rhombus .

As we know that all sides in rhombus are equal in length .

Firstly we calculate the another diagonal of rhombus .

As we know that diagonal are perpendicular bisector in rhombus . So we apply here the Pythagoras Theorem for calculating the another diagonal of the rhombus .

Let the another diagonal be x centimetres

➻ x² + 5² = 8² ⠀⠀⠀⠀⠀⠀⠀----(by Pythagoras Theorem)

➻ x² + 25 = 64

➻ x² = 64-25

➻ x² = 39

➻ x = √39 m

Now, calculating the area of the rhombus .

Area of Rhombus = 1/2 × d1 × d2

Putting the value we get

➻ Area of Rhombus = 1/2 × 8× √39

➻ Area of Rhombus = 1/2 × 8√39 cm²

➻ Area of Rhombus = 1/2× 49.95 ≈ 50cm²

➻ Area of Rhombus = 25 cm²

Hence the area of Rhombus is 25cm².