2. Write the H.C.F of two consecutive even numbers.
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Answered by
3
Answer:
2
Step-by-step explanation:
Let 2n,(2n+2) are two consecutive even Numbers.
2n = 2×n
2n+2 = 2(n+2) = 2×(n+2)
HCF(2n,2n+2)= 2
>> Product of the smallest power of each common prime factors of the numbers.
.°. H. C. F. of any two consecutive even numbers = 2
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Answered by
23
________________________________
The set of natural numbers is
(N)=
{1.2,3,4,5,........}
.
Among these natural numbers 2,4,6,8,.......are odd consecutive ones.
It is evident that 2 is the only common factor (except-1)
between two consecutive even natural number.
So HCF of two consecutive even natural numbers is 2.
{ Since 2 is highest among the factors of the consecutive even natural numbers]
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