2. Write the Nernst equation to calculate the cell potential of Mg/Mg(aq)//Ag (aq)Ag
Answers
Answered by
0
Explanation:
ANSWER
E
cell
=(0.059/2)logK
c
∵E
cell
=E
OP
Mg
o
+E
RP
Ag
o
for the change
Mg+2Ag
+
→Mg
2+
+2Ag
or E
OP
Mg
o
+E
RP
Ag
o
=(0.059/2)logK
c
or 2.37+0.80=(0.059/2)logK
c
or logK
c
=107.457 and E
cell
o
=3.17V
For maximum work −ΔG
o
=W
max
W
max
=nF×E
o
=2×96500×3.17=6.118×10
5
joule
=6.118×10
2
kJ
Hence, the correct option is A
Answered By
toppr
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