Question

2. Write the Nernst equation to calculate the cell potential of Mg/Mg(aq)//Ag (aq)Ag​

Answer 1

Explanation:

ANSWER

E

cell

=(0.059/2)logK

c

∵E

cell

=E

OP

Mg

o

+E

RP

Ag

o

for the change

Mg+2Ag

+

→Mg

2+

+2Ag

or E

OP

Mg

o

+E

RP

Ag

o

=(0.059/2)logK

c

or 2.37+0.80=(0.059/2)logK

c

or logK

c

=107.457 and E

cell

o

=3.17V

For maximum work −ΔG

o

=W

max

W

max

=nF×E

o

=2×96500×3.17=6.118×10

5

joule

=6.118×10

2

kJ

Hence, the correct option is A

Answered By

toppr

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