Question

2. Write the outer electronic configuration
of the following using orbital notation
method. Justify.
A. Ge (belongs to period 4 and group 14)
B. Po (belongs to period 6 and group 16)
C. Cu (belongs to period 4 and group 11)​

Answer 1

Answer:

Ge = $4s^{2},4p^{2}$

Po = $5d^{10},6p^{4}$

Cu = $3d^{10},4s^{1}$

Explanation:

Atomic number of Ge = 32

Outer electronic configuration of Ge is-

Ge = $4s^{2},4p^{2}$

Atomic number of Po = 84

Outer electronic configuration of Po is-

Po = $5d^{10},6p^{4}$

Atomic number of Cu = 29

Outer electronic configuration of Cu is-

Cu = $3d^{10},4s^{1}$