Question

2. Write the solubility product
expression for the electrolyte A2B3?
(where 2 and 3 are subscripts)​

Answer 1

Answer:

108s^5

Explanation:

Since the compound A2B3 dissociates as 2A and 3B. Let the solubility be s

Therefore corresponding values for A and B are 2s and 3s

Raising them to their respective powers gives 4s^2 and27s^3

Ksp=108s^5

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