Question

2. Write True (T) or False (F) against each of the following statements :

(a) 16:24 :: 20:30 (b) 21:6:: 35:10 (c) 12:18::28:12​


#Need Explanation​

Answer 1

Step-by-step explanation:

Product of the extreme terms =16×30=480=16×30=480

Product of the middle terms =24×20=480=24×20=480

∴∴ The given statement (a)→(T)(a)→(T)

bb 21:6::35:1021:6::35:10

Product of the extrome terms =21×10=210=21×10=210

Product of the middle terms =6×35=210=6×35=210

∴∴ The given statement (b)→(T)(b)→(T)

cc 12: 18 :: 28: 12

Product of the extreme terms =12×12=144=12×12=144

Product of the middle terms =18×28=504=18×28=504

Since 144eq504144eq504

∴∴ The given statement (c)→(F)(c)→(F)

dd 8:9::24:278:9::24:27

Product of the extreme terms =8×27=216=8×27=216

The product of the middle terms =9×24=216=9×24=216

∴∴ The given statement (d)→(T)(d)→(T)

ee 5.2:3.9::3:45.2:3.9::3:4

Product of the extreme terms 

Answer 2

Qᴜᴇsᴛɪᴏɴ :-

$\bf (a) \: 16:24 :: 20:30$

Sᴏʟᴜᴛɪᴏɴ :-

$\bf ➪ \: 16 : 24 = \frac{16 \div 8}{24 \div 8} = \frac{2}{3} = 2 : 3 \\ \\ \bf 20 : 30 = \frac{20 \div 10}{30 \div 10} = \frac{2}{3} = 2 :3 \\\\\bf Therefore 16 : 24 = 20 : 30 \: \bf \green{( True ).}$

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Qᴜᴇsᴛɪᴏɴ :-

$\bf (b) \: 21:6 :: 35:10$

Sᴏʟᴜᴛɪᴏɴ :-

$\bf ➪ \: 21: 6= \frac{21\div 3}{6 \div 3} = \frac{7}{2} = 7 : 2\\\\\bf 35: 10 = \frac{35 \div 5}{10 \div 5} = \frac{7}{2} = 7 :2 \\\\\bf Therefore \: 21 : 6 = 35 : 10 \: \bf \green{ ( True ).}$

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Qᴜᴇsᴛɪᴏɴ :-

$\bf (c) 12:18::28:12$

Sᴏʟᴜᴛɪᴏɴ :-

$\bf ➪ \: 12: 18= \frac{12\div 6}{18 \div 6} = \frac{2}{3} = 2: 3\\\\\bf 28: 12= \frac{28 \div 4}{12 \div 4} = \frac{7}{3} = 7 :3 \\\\\bf Therefore \: 12 : 18 ≠28 : 12 \: \bf \green {(false).}$

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