Question

2^x+1×2^3y+1 = 8 and 2^x+2×2^y+2 = 16

Answer 1

Step-by-step explanation:

Solution:

x + 2y = 5

Put the value of x = 0 in the equation x + 2y = 5

0 + 2y = 5

2y = 5

2y/2 = 5/2

y = 5/2

(0, 5/2)

Put the value of y = 0,

x + 2 × 0 = 5

x = 5

(5, 0)

Put the value of x = 2,

2 + 2y = 5

2 – 2 + 2y = 5 - 2

2y = 3

2y/2 = 3/2

y = 3/2

(2, 3/2)

Put the value of y = 2,

x + 2 × 2 = 5

x + 4 = 5

x + 4 – 4 = 5 – 4

x = 1

(1, 2)