Question

2 (x-1)²=4x² - 2x + 1 find quadratic equation​

Answer 1

Answer:

2(x-1)²=4x²-2x+1

using (a-b)²=a²+b²-2ab

2(x²+1-2x)=4x²-2x+1

2x²-4x+2=4x²-2x+1

0=4x²-2x²-2x+4x+1-2

2x²+2x-1=0

Answer 2

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$2(x - 1) ^{2} = {4x}^{2} - 2x + 1 \\ = > 2({x}^{2} - {y}^{2} + 2x) = {4x}^{2} - 2x + 1 \\ = > {2x}^{2} - {2y}^{2} + 4x = {4x}^{2} - 2x + 1 \\ = > {2x}^{2} - {4x}^{2} - {2y}^{2} + 4x + 2x - 1 = 0 \\ = > { - 2x}^{2} - {2y}^{2} + 6x - 1 = 0$

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Hope it helps u

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Ansh♤