2(x+1)^2-5(x+1)=12 ,solve using factorization method.
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Answer:
x1 = 3, x2 = -5/2
Step-by-step explanation:
2(x+1)^2-5(x+1)=12
<=> 2(x^2 + 2x + 1) - 5x - 5 - 12 = 0
<=> 2x^2 + 4x + 2 - 5x - 5 - 12 = 0
<=> 2x^2 - x - 15 = 0
Denta = (-1)^2 - 4.2.(-15) = 121 => sqrt (denta) = 11
=> x1 = [- (-1) + 11 ]/ 4 = 3
x2 = [- (-1) - 11 ]/ 4 = -5/2
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