Question

2^x/1+2^x=1/4 then find value of 8^x,/1+8^x=?
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Answer 1

check the attachment

hope it helps

Answer 2

The required value is $\dfrac{1}{28}$

Step-by-step explanation:

Since we have given that

$\dfrac{2^x}{1+2^x}=\dfrac{1}{4}$

So, it becomes,

$4.2^x=1+2^x\\\\4.2^x-2^x=1\\\\2^x(4-1)=1\\\\2^x=\dfrac{1}{3}$

So, now,

$\dfrac{8^x}{1+8^x}\\\\=\dfrac{2^{3x}}{1+2^{3x}}\\\\=\dfrac{(\dfrac{1}{3})^3}{1+(\dfrac{1}{3})^3}\\\\=\dfrac{\dfrac{1}{27}}{\dfrac{27+1}{27}}\\\\=\dfrac{1}{28}$

Hence, the required value is $\dfrac{1}{28}$

# learn more:

If 2^x/1+2^x = 1/4 then find the value of 8^x/1+8^x​

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