2^x+1=3^1-x then find that value of x
Answers
Answered by
6
2^(x +1) = 3^(1 - x)
take log both sides,
(x +1) log2 = (1 - x)log3
x.log2 + log2 = log3 - xlog3
x( log2 + log3 ) = log3 - log2
x. log(2×3) = log(3/2)
x = log(3/2)/log6
hence, x = log(3/2)/log6
take log both sides,
(x +1) log2 = (1 - x)log3
x.log2 + log2 = log3 - xlog3
x( log2 + log3 ) = log3 - log2
x. log(2×3) = log(3/2)
x = log(3/2)/log6
hence, x = log(3/2)/log6
Similar questions