Question

2(x-1)-3(4x+1)=2(x-1)-3(5x-4)+6x​

Answer 1

Step-by-step explanation:

2x-2-12x-3=2x-2-15x+12+6x

2x-2-12x-3=-13x+10+6x

2x-2-12x-3=-7x+10

-10x-5+7x-10

-3x-15=0

x=-5 OK friend

Answer 2

$\huge\bold{\gray{\sf{Answer:}}}$

$\bold{Explanation:}$

$\sf 2(x - 1) - 3(4x + 1) = 2(x - 1) - 3(5x - 4) + 6x$

$\sf= > 2x - 2 - 12x - 3 = 2x - 2 - 15x + 12 + 6x$

$\sf= > 2x - 12x - 2x + 15x - 6x - 2 - 3 + 2 - 12 = 0$

$\sf= > 2x - 14x + 9x - 3 - 12 = 0$

$\sf= > - 12x + 9x - 15 = 0$

Taking like terms together:

$\sf = > - 3x = 15$

$\sf= > x = \dfrac{15}{ - 3} = - 5$

$\huge\bold{x = - 5}$

Check:

Taking LHS

$\sf= > 2( - 5 - 1) - 3[4( - 5) + 1]$

$\sf= > - 12 - 3( - 20 + 1)$

$\sf= > - 12 - 3( - 19)$

$\sf= > - 12 + 57$

$\sf= > 45$

Taking RHS

$\sf= > 2( - 5 - 1) - 3[5( - 5) - 4]+ 6( - 5)$

$\sf = > - 12 - 3( - 25 - 4) - 30$

$\sf = > - 12 + 87 - 30$

$\sf= > 75 - 30$

$\sf= 45$

$\therefore$LHS=RHS