2(x-1) -3(x-2)=4(x-3)+5(x4)
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On the number line, we mark zeros of the function, 1, −2, 3 and −6 (with black circles) and the points of discontinuity 0 and 7 (with white circles), isolate the double points: −2, and 0, and draw the curve of signs as shown in Fig. From the graph, we get the following: (a) x ∈ (−∞, −6) ∪ (1, 3) ∪ (7, ∞) (b) x ∈ (−∞, −6] ∪ {−2} ∪ [1, 3] ∪ (7, ∞) (c) x ∈ (−6, −2) ∪ ( −2, 0) ∪ (0, 1) ∪ (3, 7) (d) x ∈ [−6, 0) ∪ (0, 1] ∪ [3, 7)Read more on Sarthaks.com - https://www.sarthaks.com/541951/let-us-consider-f-x-x-1-3-x-2-4-x-3-5-x-6-x-2-x-7-3-solve-the-following-inequalities?show=541956#a541956
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