Math, asked by mahakulsushama, 6 months ago

2/x+1 - 6/2x-1 + 3/3x+2 = 0​

Answers

Answered by amitnrw
0

Given : 2/(x + 1)  -  6/(2x - 1) + 3/(3x + 2)  = 0

To Find : Solve for x

Solution:

2/(x + 1)  -  6/(2x - 1) + 3/(3x + 2)  = 0

=> 2/(x + 1)  + 3/(3x + 2)  = 6/(2x - 1)

=>  (6x + 4 + 3x +3)/(x + 1)(3x + 2)  = 6/(2x - 1)

=> (9x + 7) /(x + 1)(3x + 2)  = 6/(2x - 1)

=> (9x + 7)(2x - 1)  = 6 (x + 1)(3x + 2)

=> 18x² + 5x - 7 = 6(3x²  + 5x + 2)

=>  18x² + 5x - 7 = 18x² + 30x + 12

=> 25x = -19

=> x = -19/25

Verification :

2/(-19/25 + 1)  - 6/(2*(-19/25) - 1)  + 3/(3(-19/25 + 2)

= 50/6  - 150/-63 +  75/-7

= 25 ( 2/6  + 6/63  - 3/7)

= 25 ( 1/3 + 2/21 - 3/7)

= 25 ( 7/21 + 2/21 - 9/21)

= 25 ( 7 + 2 - 9)/21

= 25 (0)

= 0

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