Question

2
+
X
11
- ay+bVx² + y?
b x²
y+√x + ?​

Answer 1

Step-by-step explanation:

We have,

$\frac{ {x}^{2} }{y + \sqrt{ {x}^{2} + {y}^{2} } }$

$= \frac{ {x}^{2} (y - \sqrt{ {x}^{2} + {y}^{2} } )}{(y + \sqrt{ {x}^{2} + {y}^{2} })(y - \sqrt{ {x}^{2} + {y}^{2} }) }$

$= \frac{ {x}^{2} (y - \sqrt{ {x}^{2} + {y}^{2} }) }{ {y}^{2} - {x}^{2} - {y}^{2} }$

$= \frac{ {x}^{2} (y - \sqrt{ {x}^{2} + {y}^{2} }) }{ - {x}^{2} }$

$= ( - 1)y + (1) \sqrt{ {x}^{2} + {y}^{2} }$

Hence,

a = b = 1