Math, asked by nallaamulya27, 9 days ago

2[x^2+1/x^2]-3[x+1/x]-1=0​

Answers

Answered by yadavaditya4813
1

Answer:

2(x2+1/x2)-3(x-1/x)-1=O x4+1/x-3x+3/x-1=0 x+4/x-1=0 x^2-x +4=0 x=-(-1)±{v(-1)^2-4x1×4}/2x1 x=1+v(-15)/2

Step-by-step explanation:

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Answered by Ardelinegrande
0

Answer:

Simple !!!!!!!!!! the awnser is 2, 1/2

We read it as ( Two comma one by two )

PLEASE MARK ME AS BRAINLIEST , I WOULD BE THANKFUL BE YOU !!!!!!

hope it HELPED

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