Math, asked by iamherekapil, 1 year ago

2^x-2 - 2^x+1 = 0 , find the answer .​

Answers

Answered by Daknam
7

 {2}^{2x - 4}  -  {2}^{x + 1}  = 0

 {2}^{2x - 4}  =  {2}^{x + 1}

equation of power

2x - 4 = x + 1

2x - x = 5

x = 5

Answered by CuteLegend03
0

Answer:

2) A) circle with radius 63 cm ..

\bold \orange{given:-}given:−

\fbox \green{.given \: radius \: is \: 63 \: cm}

.givenradiusis63cm

\mathfrak \red{solution:-}solution:−

\bold \purple{let \: the \: radius \: be \: r}lettheradiusber

\bold \blue{so \: c = 2 \: \pi\: r}soc=2πr

\bold \orange{ = 2 \times \frac{22}{7} \times 63}=2×

7

22

×63

\bold \green{ = 44 \times 9}=44×9

\fbox \red{ = 396 \: cm.}

=396cm.

____________❤_____________

2) B) A circle with diameter 8.4 m

\bold \orange{given:-}given:−

\fbox \green{.given \: diameter \: is \: 8.4\: m}

.givendiameteris8.4m

\huge \fbox \pink{we \: know \: that:-}

weknowthat:−

\bold \red{r = \frac{diameter}{2} }r=

2

diameter

\bold \gray{ = \frac{8.4}{2} }=

2

8.4

\fbox \blue{now \: radius \: is \: 4.2 \: m}

nowradiusis4.2m

\bold \orange{so \: c = 2\pi \: r}soc=2πr

\bold \green{ = 2 \times \frac{22}{7} \times 4.2}=2×

7

22

×4.2

\bold \purple{ \frac{44}{7} \times 42}

7

44

×42

\bold \gray{ \frac{184.8}{7} }

7

184.8

\fbox \red{26.4 \: m}

26.4m

_____________❤_____________

Answered by CuteLegend03
11

Answer:

2) A) circle with radius 63 cm ..

\bold \orange{given:-}given:−

\fbox \green{.given \: radius \: is \: 63 \: cm}

.givenradiusis63cm

\mathfrak \red{solution:-}solution:−

\bold \purple{let \: the \: radius \: be \: r}lettheradiusber

\bold \blue{so \: c = 2 \: \pi\: r}soc=2πr

\bold \orange{ = 2 \times \frac{22}{7} \times 63}=2×

7

22

×63

\bold \green{ = 44 \times 9}=44×9

\fbox \red{ = 396 \: cm.}

=396cm.

____________❤_____________

2) B) A circle with diameter 8.4 m

\bold \orange{given:-}given:−

\fbox \green{.given \: diameter \: is \: 8.4\: m}

.givendiameteris8.4m

\huge \fbox \pink{we \: know \: that:-}

weknowthat:−

\bold \red{r = \frac{diameter}{2} }r=

2

diameter

\bold \gray{ = \frac{8.4}{2} }=

2

8.4

\fbox \blue{now \: radius \: is \: 4.2 \: m}

nowradiusis4.2m

\bold \orange{so \: c = 2\pi \: r}soc=2πr

\bold \green{ = 2 \times \frac{22}{7} \times 4.2}=2×

7

22

×4.2

\bold \purple{ \frac{44}{7} \times 42}

7

44

×42

\bold \gray{ \frac{184.8}{7} }

7

184.8

\fbox \red{26.4 \: m}

26.4m

_____________❤_____________

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