Question

2^x+2 + 2^x-1 = 9
Find the value of x.

Answer 1

Answer:

$given \: that \: \\ {2}^{x } + 2 + {2}^{x} - 1 = 9 \\ {2}^{x} + {2}^{x} = 9 - 1 \\ {2}^{{x}^{2} } = 8 \\ {2}^{ {x}^{2} } = {2}^{3} \\ {x}^{2} = 3$

$x = \sqrt{3}$

Step-by-step explanation:

I hope it will help...

Answer 2

$x$x2+2+2x$x$-1=9

$x$x4+2-1=9

$x$x4=9-2+1

$x$x4=8

$x$ = $\frac{8}{2}$

$x$ = 2