Question

2*x-2 × 3*2x-2 = 36 what is the answer of x
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Answer 1

Step-by-step explanation:

Ex 6.2, 5

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Find the intervals in which the function f given by

f (x) = 2x³ 3x² 36x + 7 is

(a) strictly increasing

(b) strictly decreasing

f(x) = 2x³ 3x² - 36x + 7

Calculating f'(x)

f'(x) = 6x² - 6x - 36 +0

f'(x) = 6 (x²-x-6)

f'(x) = 6(x²-3x + 2x - 6)

f'(x) = 6(x(x-3) + 2(x-3))

f'(x) = 6(x-3) (x + 2)