Question

2(x-2)+3(4x-1)=0 check to LHS and RHS​

Answer 1

Answer:

the answer is a half

Step-by-step explanation:

First open the brackets

      2x - 4 + 12x -3 = 0

Afterwards put the like terms together

   2x + 12x -4 - 3 = 0

   14x - 7 = 0

carry seven to the other side and the sign will change to positive

     14x = 0 + 7

      14x = 7

divide both side by 14

       x = 1.5

Answer 2

Step-by-step explanation:

given that 2x(x-2)+3(4x-1)=0

to check LHS=RHS

then:-. find the value of X

so:- 2(x-2)+3(4x-1)=0

=2.x-2×2+3.4x-3×1=0

=2x-4+12x-3=0

=2x+12x-4-3=0

=14x-7=0

=14x=+7

X=7/14 i.e 1/2

verification :-

p(X)=14x-7=0

p(0)=14×1/2-7=0

p(0)=+7-7=0

p(0)=0=0

therefore LHS=RHS

this is the answer for this question

hope it helps u