Question

2(x-2)+3(4x-1)=0 solve and check?
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Answer 1

${\huge{\underline{\boxed{\red{\mathcal{Answer}}}}}}$

Given:

• 2(x-2) + 3(4x-1) = 0

To Find:

• Value of x

Solution:

$\implies 2(x-2) + 3(4x-1) = 0 \\\\ \implies 2x - 4 + 12x - 3 = 0 \\\\ \implies 14x - 7 = 0 \\\\ \implies 14x = 7 \\\\ \implies x = \dfrac{7}{14} \\\\ \bold {\implies x = \dfrac{1}{2}}$

Verification:

$\implies 2(x-2) + 3(4x-1) = 0 \\\\ \implies 2\left(\dfrac{1}{2} - 2\right) + 3\left(4\dfrac{1}{2} - 1\right) = 0 \\\\ \implies 2\dfrac{-3}{2} + 3\times 1 = 0 \\\\ \implies -3 + 3 = 0 \\\\ \implies 0 = 0. Hence \:Proved!!!!$

Hope it helps!!!