Question

2(x-2)+3(4x-1)=0, solve and verify the answer

Answer 1

$\boxed{Explained\:Answer}$

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2x-4+12x-3=0

14x-7=0

14x=7

x=7/14

x=1/2

Answer 2

Given Linear equation in one variable x :

2(x-2) + 3(4x-1) = 0

/* Open the paranthesis , we get */

$\implies 2x - 4 + 12x - 3 = 0$

/* Rearranging the like terms */

$\implies 2x + 12x - 4 - 3 = 0$

$\implies 14x - 7 = 0$

/* Add both sides by 7 , we get */

$\implies 14x - 7 + 7 = 7$

$\implies 14x = 7$

/* On Dividing bothsides by 14, we get */

$\implies x = \frac{1}{2}$

Therefore.,

$\red { Value \: of \: x } \green { = \frac{1}{2}}$

Verification:

$Substitute \: x = \frac{1}{2} \: in \:the\: equation$

$LHS = 2[ \frac{1}{2} - 2 ] + 3[ 4 \times \frac{1}{2}-1] \\= 2[ \frac{1-4}{2}] + 3( 2-1) \\= 2 \times \frac{-3}{2} + 3 \\= - 3 + 3 \\= 0 \\= RHS$

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