Question

2 (x-2)+ 3 (4x-l)=0​

Answer 1

$\huge \star \: \bf \underbrace {ANSWER} \: \star$

‣ Given :

$\sf {2(x - 2) + 3(4x - 1) = 0}$

‣ To Find :

$\textsf {The value of x}$

‣ Solution :

→ $\sf {2(x - 2) + 3(4x - 1) = 0}$

→ $\sf {2x - 4 + 12x - 3 = 0}$

→ $\sf {14x - 7 = 0}$

→ $\sf {14x = 7}$

→ $\sf {x = \frac {7}{14}}$

→ $\sf {x = \frac{1}{2}}$

$\implies \textbf {Hence, the value of x is} \: \frac {1}{2} \:.$

____________________☆

Answer 2

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$\bf\huge{\underline{\gray{✈︎Given:}}}$

$\bf{\gray{:→}}$ 2( x -2 ) + ( 4x -1 ) = 0

$\bf{\gray{▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬}}$

$\bf\huge{\underline{\gray{✈︎To~find:}}}$

$\bf{\gray{:→}}$ Value of x

$\bf{\gray{▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬}}$

$\bf\huge{\underline{\gray{✈︎Answer:}}}$

$\bf{\gray{:→}}$ 2( x -2 ) + ( 4x -1 ) = 0

$\bf{\gray{:→}}$ 2 x - 4 + 12 x - 3 = 0

$\bf{\gray{:→}}$ 14 x - 7 = 0

$\bf{\gray{:→}}$ 14 x = 7

$\bf{\gray{:→}}$ x = $\bf\dfrac{7}{14}$

$\bf{\gray{:→}}$ x = $\bf\dfrac{1}{2}$

$\bf{\bold{\gray{\therefore The~Answer~is~\dfrac{1}{2}}}}$

$\bf{\gray{▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬}}$