Question

2/x +2/3y=1/6;2/x -1/y=1
solve the following pairs of linear equation​

Answer 1

Answer:

$\large\boxed{\sf{x=4,\;\;y=-2}}$

Step-by-step explanation:

Given pair of linear equations,

2/x + 2/3y = 1/6 ......(i)

2/x - 1/y = 1 ..........(ii)

Now, subtracting eqn (ii) from (i), we get,

=> 2/3y - (-1/y) = 1/6 - 1

=> 2/3y + 1/y = (1-6)/6

=> (2+3)/3y = -5/6

=> 5/3y = -5/6

Now, cross multiplication,

=> -5 × 3y = 5 × 6

=> -3y = 6

=> y = -6/3

=> y = -2

Now, substituting the value of y in eqn (i),

=> 2/x - 2/6 = 1/6

=> 2/x = 1/6 + 2/6

=> 2/x = (1+2)/6

=> 2/x = 3/6

=> 2/x = 1/2

On cross multiplication, we get,

=> x × 1 = 2×2

=> x = 4

Hence, the values of x = 4 and y = -2