Question

2/x+2/3y=1/6
3/x+2/y=0
Simultaneous equation

Answer 1

Answer:

y=1/6, x=-1/4

Step-by-step explanation:

• Assume 2/x+2/3y=1/6 is the first equation. And 3/x+2/y=0 is the second equation.
• Multiply the first equation by 6xy to get rid of the denominator, so you will get 12y+4x=1, which is your third equation. Same for the second equation, multiply it by xy to get rid of the denominator, so you will get 3y+2x=0 as your fourth equation.

• Multiply the fourth equation by 2 to get 6y+4x=0 as your fifth equation.  So now you will have the same x coefficient for both the fifth and third equation.
• Minus equation 5 from equation 3 and you'll get 6y=1, so y=1/6
• Substitute the value of y into the fourth equation, so it's 3(1/6)+2x=0. Therefore 2x=-1/2, then bring 2 over so x=(-1/2)/2 and x=-1/4