Question

2^x×2^y=16
2^x/2^y=2 do it by elimination method
​

Answer 1

Step-by-step explanation:

given-2^x×2^y=16

and 2^x×2^y=2

by elemination method--

2^(x+y)=2^4

therefore. (x+y)=4

x=4-y -(1)

by putting the value of (x) in 2nd equation--

2^x×2^y=2

2^(x+y)=2^1

(x+y)=1

4-y+y=1

=-3

Answer 2

Answer:

2

$\sqrt{2223 \sqrt[ \\ ]{?} }$