Question

−2(x
2
−y
2
+xy)−3(x
2
+y
2
−xy)​

Answer 1

Answer:

Step-by-step explanation:

We know sum of GP

Sn​=r−1a(rn−1)​ when r>1

Where a= first term, n=nth term and r is common ratio

Given sequence (x+y),(x2+xy+y2),(x3+x2y+xy2+y3),.... to n terms.

Multiplying and dividing each term by (x−y), we get the given sum as

(x−y)1​⋅{(x2−y2)+(x3−y3)+(x4−y4)+.... to n term}

=(x−y)1​⋅{(x2+x3+x4+... to n terms )−(y2+y3+y4+.... to n terms)}

=(x−y)1​⋅{x2(x−1xn−1​)−y2(y−1yn−1​)}.

hope this is helpfull

Answer 2

$-2(x^2-y2+xy) -3(x^2+y^2-xy)\\-2x^2 + 2y^2 -2xy - 3x^2 - 3y^2 +3xy\\-5x^2 -y^2 +xy\\xy - y^2 - 5x^2$

Point:-

.) Never Put Negative signs on the starting

.) If all are Negative then it's ok

Have a gr8 day!!