Question

2^x + 22^x + 222^x / 3^x + 33^x + 333^x = 9/4, then x is equal to?

I'm asking this again. Please answer.​

Answer 1

I Guess it should be 4/9 instead of 9/4..For this take out 2^x common from numerator and 3^x common from denominator and the common factor i.e; (1+11^x+111^x) gets cancelled out.. Hence x should be 2

Answer 2

Answer:

x = -2

Step-by-step explanation:

2^x + 22^x + 222^x / 3^x + 33^x + 333^x = ( 4/9 )^-1

2^x ( 1 + 11 + 111 ) / 3^x (1 + 11 + 111) = ((2/3)^2)^-1

2^x / 3^x =  (2/3)^-2

(2/3)^x = (2/3)^-2

x = -2

So the value of x is -2