Question

(2 x-2x)+3 x-3)+(4 x-4)=1

Answer 1

Answer:

$\left(2x-2x\right)+\left(3x-3\right)+\left(4x-4\right)=1\quad :\quad x=\dfrac{8}{7}\quad \left(\mathrm{Decimal}:\quad x=1.14286\dots \right)$

Step-by-step explanation:

$\left(2x-2x\right)+\left(3x-3\right)+\left(4x-4\right)=1$

$\gray{\mathrm{Remove\:parentheses}:\quad \left(a\right)=a}$

$2x-2x+3x-3+4x-4=1$

$\gray{\mathrm{Group\:like\:terms}}$

$2x-2x+3x+4x-3-4=1$

$\gray{\mathrm{Add\:similar\:elements:}\:2x-2x+3x+4x=7x}$

$7x-3-4=1$

$\gray{\mathrm{Subtract\:the\:numbers:}\:-3-4=-7}$

$7x-7=1$

$\gray{\mathrm{Add\:}7\mathrm{\:to\:both\:sides}}$

$7x-7+7=1+7$

$\gray{\mathrm{Simplify}}$

$7x=8$

$\gray{\mathrm{Divide\:both\:sides\:by\:}7}$

$\dfrac{7x}{7}=\dfrac{8}{7}$

$\gray{\mathrm{Simplify}}$

$x=\dfrac{8}{7}$