Question

2^x+3-2^x+1=96 find x

Answer 1

2^x+3 - 2^x+1 =96

2^x * 2³ - 2^x * 2 =96{ since a^m+n = a^m * a^n}

8*2^x - 2*2^x =96
6* 2^x =96
2^x = 96/6
2^x =16

2^x = 2^4{ since if a^m = a^n then m=n}
therefore
x= 4