Question

2^x-3×3^2x-8=36find the value of x

Answer 1

2^x × 2^-3 ×3^2x × 3^-8=36

2^x × {1/8} × 3^2x × 1/6561=36

2^x × 9^x ×1/52488=36

18^x = 36×52488

x= log to base 18 (1889568)

X~=5(rounding off)