Question

(2 x+3)(3 x²-x-2) solve the number and answer​

Answer 1

Answer:

Given,

3^(x²-x)+4^(x²-x)=25

We know that

3²+4² =25

So

3^(x²-x)+4^(x²-x)= 3^2 +4^2

It implies that

(x²-x) =2

Or

x²-x-2 =0

(x-2)(x+1)=0

x=-1 or 2

Therefore the solutions to the given equation are (-1) and 2 .

I hope it helps you

Answer 2

Answer:

x^2/(x-3)=(x+2)/(2*x-5) we can clear both denoms to get

x^2*(2*x-5)=(x+2)*(x-3), expand out and move to the LHS to get

2*x^3–5*x^2=x^2+2*x-3*x-6 so

2*x^3–5*x^2-x^2+x+6=0 or

2*x^3–6*x^2+x+6=0

This factors as (x-2)*(2*x^2–2*x-3)=0 so the roots are

x={2,(sqrt(7)+1)/2,(sqrt(7)-1)/2}

None of the roots yield a zero denominator, and are readily verified as solutions.