Math, asked by rita47, 1 year ago

2(x-3)+3(y-5)=0,5(x-1)+4(y-4)=0.
please solve it
I will mark you as brainlist

Answers

Answered by Panzer786
69
Hiii friend,

2(X-3) +3(Y-5) = 0

2X -6 +3Y -15 = 0

2X +3Y = 21.....(1)

5(X-1) +4(Y-4) = 0

5X -5 +4Y -16 = 0

5X +4Y = 21.......(2)

From equation 1 we get,

2X + 3Y = 21

2X = 21-3Y

X= 21-3Y/2.......(3)

Putting the value of X in equation (2)

5X + 4Y = 21

5 × (21-3Y/2) +4Y = 21

105 -15Y/2 +4Y = 21

105-15Y + 8Y = 21 × 2

-7Y = 42-105

-7Y = -63

Y = 63/7 = 9

Putting the value of X in equation (3)

X = 21-3Y/2 = 21 - 3 × 9/2 = 21 -27/2 = -6/2 =-3.

Hence,

X = -3 and Y = 9

HOPE IT WILL HELP YOU.... :-)

rita47: thank you
Answered by pari089
11

Answer:

X=-3

Y=9.

.hope it's help u Mark me as a brain list

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