Math, asked by anwarjahan070, 4 days ago

2(x-3) + 3(y-5)=0 5(x-1) + 4(y-4)=0 using elemanitaion by substitution

Answers

Answered by dasn7461

1

Answer:

2(x-3)+3(y-5)=0

5(x-1) +4(y-4)=0

Step-by-step explanation:

2x-6-3y-15=0 5x-5+4y-16=0

2x-3y-21=0. 5x+4y -21=0

2x-3y=21. 5x+4y=21

2x-5x-3y-4y=0

-3x-7y=0

-(-3)x-7y=0

3x -7y =0

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