Question

(2^x+3) -9 ×( 2^x) +1=0 ​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

We have:

($2^{x+3}$) - 9 × ($2^{x}$) + 1 = 0

We have to find, the value of x.

Solution:

∴ ($2^{x+3}$) - 9 × ($2^{x}$) + 1 = 0

⇒ $2^{x}2^{3}$ - 9 × ($2^{x}$) + 1 = 0 [ ∵ $a^{m+n}=a^{m}.a^{n}$ ]

⇒ $8(2^{x})$ - 9 ($2^{x}$) + 1 = 0

⇒ - $2^x$ + 1 = 0

⇒ $2^x$ = 1

⇒ $2^x$ = $2^0$

Comparing the powers of x, we get

x = 0

∴ x = 0

Thus, the value of x is "equal to 0".