Math, asked by ashimas0130, 10 months ago

2^x+3-9×2^x+1=0
find the value of x​

Answers

Answered by rajivrtp
0

Step-by-step explanation:

2^x+3-9×2^x+1 = 0

-8×2^x+4= 0

8×2^x = 4

2^x= 4 / 8= 1/2 = 0.5

x= log0. 5 to the base of 2

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