Question

√2+√x=3 find the value of x​

Answer 1

Answer:

$\sqrt{2 } + \sqrt{x} = 3 \ \\ \sqrt{x} = 3 - \sqrt{2} \\ x = (3 - \sqrt{2) {}^{2} } \\ x = 11 - 6 \sqrt{2}$

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Answer 2

Step-by-step explanation:

STEPS FOR SOLVING RADICAL EQUATIONS

$\sqrt{} 2+\sqrt{x} =3$

Subtract  Subtract  $\sqrt2$ from both sides of the equation

$\sqrt{x} + \sqrt2 - \sqrt2 = 3-\sqrt2$

Subtracting  $\sqrt2$ from itself leaves 0.

$\sqrt{x} =3-\sqrt 2$

Square both sides of the equation.

$x=11-6\sqrt2$

2.514718626

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