Math, asked by manthegentle, 8 months ago

2^x-3 (in power) = 1, find the value of x​

Answers

Answered by Cive
14

Answer:

2^x - 3 = 1

also 2^ x - 3 = 1¹

comparing the exponents

x-3 = 1

=x = 3+1

therefore, x=4

Answered by Yamini2110
0

Answer:

x=(1+3log2)/log2. log2=0.301

Step-by-step explanation:

applying log on both sides

(x-3)log2=1

x=1/(log2) +3

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