Question

2/x-3 + x/x²-9 = 4/x+3​

Answer 1

{2/(x-3)}+{x/(x^2-9)}={4/(x+3)}
than
[{2/(x-3)}-{4/(x+3)}]={x/(x^2-9 )}
and solve
x=18

Answer 2

Answer:

+x2−9x=x+34

Variable x cannot be equal to any of the values −3,3 since division by zero is not defined. Multiply both sides of the equation by (x−3)(x+3), the least common multiple of x−3,x2−9,x+3.

(x+3)×2+x=(x−3)×4

Use the distributive property to multiply x+3 by 2.

2x+6+x=(x−3)×4

Combine 2x and x to get 3x.

3x+6=(x−3)×4

Use the distributive property to multiply x−3 by 4.

3x+6=4x−12

Subtract 4x from both sides.

3x+6−4x=−12

Combine 3x and −4x to get −x.

−x+6=−12

Subtract 6 from both sides.

−x=−12−6

Subtract 6 from −12 to get −18.

−x=−18

Multiply both sides by −1.

x=18