2/x+3/y=13 5/x-4/y=-2
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Step-by-step explanation:
let, 1/x=u & 1/y=v
hence, 2u+3v=13.......(i)&
5u-4y=-2........(ii)
apply elimination method
then (i)×5=10u+15v=65
(ii)×2=10u-8y=-4
Now (i)-(ii) = 23v=69
v=3
putting the value of v in equation (i)
2u+3×3=13
=2u=4
=u=2
so, 1/x=u, 1/y=v
1/x=2,1/y=3
x=1/2 & y=1/3
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