Question

2/x+3/y=13,5/x-4/y=-2​

Answer 1

Answer:

let 1/x be a and 1/y be b

2/x+3/y=13

2a+3b=13.....equation 1

5/x -4/y=-2

5a-4b=-2....equation 2

let equation 1 be multiplied with 5

5(2a+3b)=5×13

10a+15b=65.....equation 3

let equation 2 be multiplied with 2

2(5a-4b)=2×-2

10a-8b=-4......equation 4

from equation 3 and equation 4

10a+15b-(10a-8b)=65-(-4)

10a+15b-10a+8b=65+4

23b=69

b=3

in equation 1, let substitute the value of b

2a+3b=13

2a+3(3)=13

2a+9=13

2a=13-9

2a=4

a=2

therefore, a=1/x=2

x=1/2

b=1/y=3

y=1/3

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