Question

2/x+3/y=13and 5/x-4/y=13​

Answer 1

Step-by-step explanation:

what we have to find thuestion is not cleare

Answer 2

$\frac{2}{x} + \frac{3}{y} = 13\\ \\\frac{5}{x} - \frac{4}{y} = 13$

STEP : 1

take    $\frac{1}{x}$ = a and    $\frac{1}{y}$ = b

STEP : 2

Now, the equations look like this :-

2a + 3b = 13

5a - 4b = 13

STEP : 3

Now, to solve them we have to make their coefficients of either a or b equal.

2a + 3b = 13 ------------ *4

5a - 4b = 13 ------------- *3

8a + 12b = 52   ---------------------equation 1

15a - 12b = 39  -------------------- equation 2

-----------------------

23a - 0 = 91

23a = 91

a = $\frac{91}{23}$

put this in any equation to get b

8a + 12b = 52

8( $\frac{91}{23}$ ) + 12b = 52

$\frac{728}{23}$ + 12b = 52

12b = 52 - $\frac{728}{23}$

12b = $\frac{1196-728}{23}$

b = $\frac{468}{12*23}$

b = $\frac{39}{23}$

Now, we have taken

$\frac{1}{x} = a\\\\\frac{1}{x} = \frac{91}{23}\\\\ x = \frac{23}{91}$

similarly,

$\frac{1}{y} = b\\\\\frac{1}{y} = \frac{39}{23}\\\\\ y = \frac{23}{39}$

MAYBE IT'S RIGHT...

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