2/x-3/y=15;8/x+5/y=77
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Answered by
108
HELLO DEAR,
2/x - 3/y = 15
8/x + 5/y = 77
∴ [ let 1/x = p & 1/y = q ]
Now,
2p - 3q = 15------------(1)
8p + 5q = 77-----------(2)
FROM-----(1) & -------(2)
Multiply by (4) in ----(1)
we get,
8p - 12q = 60
8p + 5q = 77
(-)___(-)___(-)
---------------------
-17q = - 17
⇒q = 1 put in --(1)
we get,
2p - 3(1) = 15
⇒2p = 15 + 3
⇒ 2p = 18
⇒p = 9
⇒1/x = 9
∴ [ 1/x = p ]
⇒x = 1/9
AND,
q = 1/y = 1
∴ [ q = 1/y ]
⇒y = 1 , x = 1/9
2/(1/9) - 3(1) = 15
⇒18 - 3 = 15
⇒15 = 15
And,
8/(1/9) + 5(1) = 77
⇒72 + 5 = 77
⇒77 = 77
I HOPE ITS HELP YOU DEAR,
THANKS
2/x - 3/y = 15
8/x + 5/y = 77
∴ [ let 1/x = p & 1/y = q ]
Now,
2p - 3q = 15------------(1)
8p + 5q = 77-----------(2)
FROM-----(1) & -------(2)
Multiply by (4) in ----(1)
we get,
8p - 12q = 60
8p + 5q = 77
(-)___(-)___(-)
---------------------
-17q = - 17
⇒q = 1 put in --(1)
we get,
2p - 3(1) = 15
⇒2p = 15 + 3
⇒ 2p = 18
⇒p = 9
⇒1/x = 9
∴ [ 1/x = p ]
⇒x = 1/9
AND,
q = 1/y = 1
∴ [ q = 1/y ]
⇒y = 1 , x = 1/9
2/(1/9) - 3(1) = 15
⇒18 - 3 = 15
⇒15 = 15
And,
8/(1/9) + 5(1) = 77
⇒72 + 5 = 77
⇒77 = 77
I HOPE ITS HELP YOU DEAR,
THANKS
Answered by
107
HEya..!!!
2/x - 3/y = 15
8/x + 5/y = 77
[ 1/x = m , 1/y = n ]
use this in Equation,
2m - 3n = 15--------------(1)
8m + 5n = 77------------(2)
from---(1) AND ------(2)
multiply by (4) in ---(1)
we get,
8m - 12n = 60
8m + 5n = 77
(-)___(-)____(-)
————————
-17n = -17
=> n = 1 put in--(2)
8m + 5(1) = 77
=> 8m = 77 - 5
=> m = 72/8
=> m = 9 , n = 1
we assumed above [ 1/x = m , 1/y = n ]
NOW,
m = 1/x = 9
=> x = 1/9
AND,
n = 1/y = 1
=> y = 1,
I HOPE ITS HELP YOU,
2/x - 3/y = 15
8/x + 5/y = 77
[ 1/x = m , 1/y = n ]
use this in Equation,
2m - 3n = 15--------------(1)
8m + 5n = 77------------(2)
from---(1) AND ------(2)
multiply by (4) in ---(1)
we get,
8m - 12n = 60
8m + 5n = 77
(-)___(-)____(-)
————————
-17n = -17
=> n = 1 put in--(2)
8m + 5(1) = 77
=> 8m = 77 - 5
=> m = 72/8
=> m = 9 , n = 1
we assumed above [ 1/x = m , 1/y = n ]
NOW,
m = 1/x = 9
=> x = 1/9
AND,
n = 1/y = 1
=> y = 1,
I HOPE ITS HELP YOU,
sneharajsharma:
thank u very much
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