Question

2/x+3/y=17, 1/x+1/y=7 solve this using the method of elimination. ​

Answer 1

Answer:

x = ¼

y = ⅓

Step-by-step explanation:

Given a pair of linear equations such that,

2/x + 3/y = 17 ........(1)

And

1/x + 1/y = 7 ..........(2)

To solve this by elimination method.

Multiply eqn (2) with 2.

Therefore, we will get,

=> 2/x + 2/y = 14 ........(3)

Now, subtracting eqn (3) from (1), we get,

=> 3/y - 2/y = 17 - 14

=> 1/y = 3

=> y = 1/3

Now, putting this value in (2), we get,

=> 1/x + 3 = 7

=> 1/x = 7 - 3

=> 1/x = 4

=> x = 1/4

Hence, value of x = ¼ and y = ⅓

Answer 2

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→ Answer :

$x = \frac{1}{4} , y = \frac{1}{3}$

→ Step-by-step explanation :

Given a pair of linear equations. We need to find the value of x and y from this equations by elimination method.

In elimination method we can use addition or subtraction.

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$\frac{2}{x}+\frac{3}{y}=17\\\\=>2y+3x=17xy...(1)\\\\\frac{1}{x} +\frac{1}{y}=7\\\\ =>y+x=7xy$

Now multiply with 2 on both sides , we get ,

$=>2y+2x=14xy...(2)$

Now (1) - (2) , we get ,

$2y+3x-(2y+2x)=17xy-14xy\\\\=>3x-2x=3xy\\\\=>x=3xy\\\\=>y=\frac{1}{3}$

sub. y = 1/3 in (2) , we get ,

$=>2(\frac{1}{3} )+2x=14x(\frac{1}{3} )\\\\=>\frac{2}{3}+2x=\frac{14x}{3}\\\\ =>\frac{6}{3}+6x=14x\\\\ =>2+6x=14x\\\\=>2=8x\\\\=>x=\frac{1}{4}$

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