Question

2^x+3^y=17,2^x+2−3^y+1=5
solve this by elimination method ​

Answer 1

Answer:

Given 2

Given 2 x

Given 2 x +3

Given 2 x +3 y

Given 2 x +3 y =17 , 2

Given 2 x +3 y =17 , 2 x+2

Given 2 x +3 y =17 , 2 x+2 −3

Given 2 x +3 y =17 , 2 x+2 −3 y+1

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2 =17

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2 =17and 2

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2 =17and 2 5

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2 =17and 2 5 −3

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2 =17and 2 5 −3 3

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2 =17and 2 5 −3 3 =32−27=5=5

Given 2 x +3 y =17 , 2 x+2 −3 y+1 =5by observation, we can say that at x=3 y=2⇒2 3 +3 2 =17and 2 5 −3 3 =32−27=5=5∴x=3y=2