2^x 3^y 5^z = 2160 find x,y,z
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Answer:
x = 4 , y = 3 , z = 1
Step-by-step explanation:
2^x 3^y 5^z = 2160
Factors of 2160 = 2*2*2*2*3*3*3*5
= 2^4*3^3*5^1
x = 4
y = 3
z = 1
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