Math, asked by heer777, 12 days ago

2^x 3^y 5^z = 2160 find x,y,z

Answers

Answered by sakshi101106
1

Answer:

x = 4 , y = 3 , z = 1

Step-by-step explanation:

2^x 3^y 5^z = 2160

Factors of 2160 = 2*2*2*2*3*3*3*5

                          = 2^4*3^3*5^1

x = 4

y = 3

z = 1

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