Question

2^x=3^y=6^z then
prove
z = xy/x+y

Answer 1

2^x=3^y=6^z=k
2=k^1/x
3=k^1/y
6=2*3=K^1/z=k^1/x * k^1/y

K^1/z=k^1/x * k^1/y
1/z= 1/x + 1/y
1/z= (x+y)/XY
z= XY/(x+y)