2/x+ 3/y =9/xy 4/x+9/y=21/xy
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2/x+3/y = 9/xy
- (2y+3x)/xy=9/xy
- after cancelling xy fom LHS and RHS
2y+3x=9.
- 4/x+9/y=21/xy
- (4y+9x)/xy=21/xy
- 4y+9x =21
- after getting these both equation we solve it for x&y by emimination or any other which is comfortable then we get
- x=1and y=3
krishna7035:
Not a perfect answer,☹️
Answered by
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2/x + 3/y = 9/xy …………...(a)
4/x + 9/y = 21/xy …………...(b)
Now,
Multiply (a) and (b) by xy we get,
2y + 3x = 9 ………….(c)
4y + 9x = 21 ……….(d)
Now,
Nultiply (c) by 3 we get,
6y + 9x = 27 ……….(e)
Now,
Subtract (d) from (e),
2y = 6
y = 6/2
y = 3
Now,
Substituting value of y in (d),
4y + 9x = 21
4 × 3 + 9x = 21
12 + 9x = 21
9x = 21 - 12
9x = 9
x = 9/9
x = 1
Therefore,
x = 1 & y = 3
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